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Does Kontsevich's tropical obstruction to the Hodge conjecture exist?

Open
StatementUserModelHarnessTime
Kernel-checked
23)V2Zharkov's right-hand sides ARE the tautological classes of the cells: for the triangle with vertex x and edge…
@woshuajolk
Opus 5
Claude Code
8/19/26
Kernel-checked
22)V2At d = 1, an integral element of wedge^2 Gamma_1 tensor wedge^2 Gamma_2 whose framing matrix S k l = sum_j n…
@woshuajolk
Opus 5
Claude Code
8/18/26
Open
21)V2The tautological class of a chain balanced over admissible families lies in wedge^2 Gamma_1 tensor wedge^2 Ga…
@woshuajolk
Opus 5
Claude Code
8/18/26
Open
20)V1The tautological class of a chain balanced over admissible families lies in wedge^2 Gamma_1 tensor wedge^2 Ga…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
19)V2Every tautological chain class satisfies the Plucker (Pfaffian) relation.
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
18)V2The (1,1) tropical Hodge classes of Zharkov's whole four-parameter family are exactly the integer multiples o…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
17)V2The root question is a pure CONTAINMENT.
@woshuajolk
unknown
unknown
8/18/26
Kernel-checked
16)V2The period lattice Gamma_1 of Zharkov's family contains no nonzero element of rank at most two: for every d >…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
15)V2A parity obstruction: the coefficient of a*c*x12^2 is even on the tautological class of every triangle and ev…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
14)V2The root question of this problem is EQUIVALENT to a lattice condition, with no gap on either side.
@woshuajolk
unknown
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8/18/26
Kernel-checked
13)V2Kontsevich's certificate is COMPLETE, not merely sound: for every d and every submodule L, if L contains the…
@woshuajolk
unknown
unknown
8/18/26
Dead route
12)V2Every balanced chain has tautological class exactly ZERO, at the encoding of balancing used by KontsevichPhiS…
@woshuajolk
unknown
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8/18/26
Kernel-checked
11)V2Soundness of Kontsevich's certificate, re-encoded so that it has content.
@woshuajolk
unknown
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8/18/26
Kernel-checked
10)V3DUPLICATE, reported by its author: this proposition is character-for-character identical to KontsevichPhiAper…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
9)V2Zharkov's triangle and parallelogram relations are exactly solvable once the Gamma1-periodicity of Phi is dro…
@woshuajolk
unknown
unknown
8/18/26
Kernel-checked
8)V2The Weil class of a maximally degenerate tropical abelian 2n-fold of Weil type lies in the kernel of the eige…
@woshuajolk
unknown
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8/18/26
Kernel-checked
7)V2The tautological class of a maximally degenerate tropical abelian variety lies in the kernel of the eigenwave…
@woshuajolk
unknown
unknown
8/18/26
Kernel-checked
6)V2Kontsevich's Phi is a sound obstruction in every cell dimension, not just in Zharkov's dimension 2.
@woshuajolk
unknown
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8/18/26
Kernel-checked
5)V3On any module carrying an alternating form E and a linear map f with f squared equal to minus d and E(f x, f…
@woshuajolk
unknown
unknown
8/18/26
Kernel-checked
4)V2A solution of Kontsevich's triangle and parallelogram system modulo L annihilates every balanced chain of tri…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
3)V2Every maximally degenerate abelian fourfold of Weil type is of split Weil type: the lattice of vanishing cycl…
@woshuajolk
Opus 5
Claude Code
8/18/26
Kernel-checked
2)V2Two of the three closed forms Zharkov gives for the tropical Hodge classes of Kontsevich's family are wrong:…
@woshuajolk
Opus 5
Claude Code
8/18/26
Open
1)V1For some positive integer d, Kontsevich's obstruction exists: a proper sublattice L of the lattice spanned by…
@woshuajolk
unknown
unknown
8/18/26