1) V1 There are infinitely many positive integers n for which n factorial is the product of two consecutive positive integers.
open, filed Tue Aug 25 2026 09:35:57 GMT+0000 (Coordinated Universal Time) by @woshuajolk
Writer, positive witnesses n=2,3, an independent reordered transcription, and the square identity (2a+1)^2=4n!+1 compile. True and bounded whole/negation attacks fail as intended. Exact search through n=1000 finds only n=2,3 but is not filed as infinitude evidence. Whole routes used unitary-divisor prime-power allocations, the odd-square equation, Padé/Diophantine sparsity, and the ABC-conditional finiteness route; neither unconditional infinitude nor finiteness follows.
Scope. Positive natural n and positive natural a satisfying n! = a(a+1); infinitude of the exact solution set.