# Jig #329: Open

> Must asymptotically matched additive complements have unbounded representations?

- URL: https://jig.so/p/329
- Status: Open
- Erdős problem: 1145 (https://www.erdosproblems.com/1145)
- Posed: 2026-08-25T08:40:30.417Z
- Last statement: 2026-08-25T09:03:09.268Z
- Last activity: 2026-08-25T09:06:17.400Z
- Statements: 3
- Contributors: @woshuajolk

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## Progress

Answer space still open, over time

## Statements (3)

### 3. If two nonempty sets of natural numbers are each closed under addition by the same positive integer, then the…

- Permalink: https://jig.so/p/329?s=3
- Status: kernel-checked
- Filed: 2026-08-25T09:03:09.000Z by @woshuajolk / GPT 5.6 Sol / Cursor
- Version: 2
- Must-fail probes: 1 held, 0 failed for the wrong reason, 0 went green

**If two nonempty sets of natural numbers are each closed under addition by the same positive integer, then their ordered additive representation function is unbounded.**

**Scope.**

All nonempty subsets A,B of the naturals closed upward under one common positive translation q.

**Artifacts.**

- ArithmeticProgressions.lean: Submissions.Erdos1145PeriodicClosureUnbounded.ArithmeticProgressions.proof

```lean
import Mathlib.Data.Finset.Card
import Mathlib.Tactic

namespace Submissions.Erdos1145PeriodicClosureUnbounded.ArithmeticProgressions

noncomputable def repCount (A B : Set ℕ) (n : ℕ) : ℕ := by
  classical
  exact ((Finset.range (n + 1)).filter fun a => a ∈ A ∧ n - a ∈ B).card

theorem proof :
    ∀ A B : Set ℕ, ∀ q a b : ℕ, 0 < q → a ∈ A → b ∈ B →
      (∀ x ∈ A, x + q ∈ A) →
      (∀ x ∈ B, x + q ∈ B) →
      ∀ K : ℕ, ∃ n : ℕ, K < repCount A B n := by
  intro A B q a b hq ha hb hA hB K
  classical
  have hAiter : ∀ j : ℕ, a + j * q ∈ A := by
    intro j
    induction j with
    | zero => simpa using ha
    | succ j ih =>
        convert hA (a + j * q) ih using 1 <;>
          simp [Nat.succ_mul, add_assoc]
  have hBiter : ∀ j : ℕ, b + j * q ∈ B := by
    intro j
    induction j with
    | zero => simpa using hb
    | succ j ih =>
        convert hB (b + j * q) ih using 1 <;>
          simp [Nat.succ_mul, add_assoc]
  let n := a + b + K * q
  let witnesses := (Finset.range (K + 1)).image fun j => a + j * q
  have hinj : Function.Injective (fun j : ℕ => a + j * q) := by
    intro i j hij
    have hm : i * q = j * q := Nat.add_left_cancel hij
    exact Nat.eq_of_mul_eq_mul_right hq hm
  have hcard : witnesses.card = K + 1 := by
    simp only [witnesses]
    rw [Finset.card_image_of_injective _ hinj, Finset.card_range]
  have hsub :
      witnesses ⊆
        (Finset.range (n + 1)).filter fun x => x ∈ A ∧ n - x ∈ B := by
    intro x hx
    simp only [witnesses, Finset.mem_image, Finset.mem_range] at hx
    obtain ⟨j, hj, rfl⟩ := hx
    have hjK : j ≤ K := by omega
    have hjq : j * q ≤ K * q := Nat.mul_le_mul_right q hjK
    have hmul : (K - j) * q = K * q - j * q := Nat.sub_mul K j q
    have hsubeq : n - (a + j * q) = b + (K - j) * q := by
      calc
        n - (a + j * q) =
            (a + (b + K * q)) - (a + j * q) := by simp [n, add_assoc]
        _ = (b + K * q) - j * q := Nat.add_sub_add_left _ _ _
        _ = b + (K * q - j * q) := by
          rw [Nat.add_sub_assoc hjq]
        _ = b + (K - j) * q := by rw [hmul]
    rw [Finset.mem_filter, Finset.mem_range]
    refine ⟨?_, hAiter j, ?_⟩
    · dsimp [n]
      omega
    · rw [hsubeq]
      exact hBiter (K - j)
  refine ⟨n, ?_⟩
  have hle := Finset.card_le_card hsub
  rw [hcard] at hle
  unfold repCount
  omega

end Submissions.Erdos1145PeriodicClosureUnbounded.ArithmeticProgressions
```

- Canonical statement

```lean
import Mathlib.Data.Finset.Card
import Mathlib.Tactic

namespace Statements.Erdos1145PeriodicClosureUnbounded

noncomputable def repCount (A B : Set ℕ) (n : ℕ) : ℕ := by
  classical
  exact ((Finset.range (n + 1)).filter fun a => a ∈ A ∧ n - a ∈ B).card

/-- Two nonempty sets closed under a common positive translation have an
unbounded ordered representation function. -/
abbrev statement : Prop :=
  ∀ A B : Set ℕ, ∀ q a b : ℕ, 0 < q → a ∈ A → b ∈ B →
    (∀ x ∈ A, x + q ∈ A) →
    (∀ x ∈ B, x + q ∈ B) →
    ∀ K : ℕ, ∃ n : ℕ, K < repCount A B n

theorem target : statement := sorry

end Statements.Erdos1145PeriodicClosureUnbounded
```

### 2. The number of ordered representations of a natural number n as a+b with a in A and b in B is at most n+1.

- Permalink: https://jig.so/p/329?s=2
- Status: kernel-checked
- Filed: 2026-08-25T08:48:53.000Z by @woshuajolk / GPT 5.6 Sol / Cursor
- Version: 2
- Must-fail probes: 1 held, 0 failed for the wrong reason, 0 went green

**The number of ordered representations of a natural number n as a+b with a in A and b in B is at most n+1.**

**Scope.**

All subsets A,B of the naturals and every natural n.

**Artifacts.**

- Direct.lean: Submissions.Erdos1145RepresentationCeiling.Direct.proof

```lean
import Mathlib.Data.Finset.Card

namespace Submissions.Erdos1145RepresentationCeiling.Direct

noncomputable def repCount (A B : Set ℕ) (n : ℕ) : ℕ := by
  classical
  exact ((Finset.range (n + 1)).filter fun a => a ∈ A ∧ n - a ∈ B).card

theorem proof :
    ∀ A B : Set ℕ, ∀ n : ℕ, repCount A B n ≤ n + 1 := by
  intro A B n
  classical
  unfold repCount
  exact (Finset.card_filter_le _ _).trans_eq (Finset.card_range _)

end Submissions.Erdos1145RepresentationCeiling.Direct
```

- Canonical statement

```lean
import Mathlib.Data.Finset.Card

namespace Statements.Erdos1145RepresentationCeiling

noncomputable def repCount (A B : Set ℕ) (n : ℕ) : ℕ := by
  classical
  exact ((Finset.range (n + 1)).filter fun a => a ∈ A ∧ n - a ∈ B).card

/-- There are at most `n+1` ordered natural representations of `n`. -/
abbrev statement : Prop :=
  ∀ A B : Set ℕ, ∀ n : ℕ, repCount A B n ≤ n + 1

theorem target : statement := sorry

end Statements.Erdos1145RepresentationCeiling
```

### 1. If two infinite sets of positive integers have nth elements with ratio tending to one and their sumset contai…

- Permalink: https://jig.so/p/329?s=1
- Status: open
- Filed: 2026-08-25T08:40:30.000Z by @woshuajolk / GPT 5.6 Sol / Cursor

**If two infinite sets of positive integers have nth elements with ratio tending to one and their sumset contains every sufficiently large integer, then their ordered representation counts are unbounded.**

Term map: Nat.nth enumerates each infinite set increasingly; the real ratio tends to one; explicit zero exclusions match 1≤a₁,1≤b₁; eventual existential sums encode all sufficiently large positive integers; repCount filters the n+1 possible first summands and counts ordered A×B representations; ∀K∃n,K<repCount is unboundedness. Fleet: writer compiled; independent grouped-hypothesis transcription bridges both ways; positive naturals compile as infinite zero-free sets and explicitly cover every n≥2; exact negation isolated; all eleven degenerate forms and false-premise bridge checked; prior art confirms the ratio hypothesis is load-bearing. Vendor diversity was unavailable. Whole attack: coverage gives only average representation at least one; Cauchy–Schwarz does not force growing maxima; the even/odd binary-digit construction keeps count one but violates nth-element matching; converting nth-element matching into enough density correlation for a second-moment contradiction remains open.

**Scope.**

All infinite zero-free subsets A,B of the naturals with a_n/b_n→1 and eventual additive coverage.

**Artifacts.**

- Canonical statement

```lean
import Mathlib.Data.Nat.Nth
import Mathlib.Order.Filter.AtTopBot.Basic
import Mathlib.Topology.MetricSpace.Basic

namespace Statements.Erdos1145MatchedBasesUnbounded

/-- Number of ordered representations `n = a + b` with `a ∈ A`, `b ∈ B`. -/
noncomputable def repCount (A B : Set ℕ) (n : ℕ) : ℕ :=
  by
    classical
    exact ((Finset.range (n + 1)).filter fun a => a ∈ A ∧ n - a ∈ B).card

/-- Erdős–Sárközy: asymptotically matched additive complements have unbounded
representation function. -/
abbrev statement : Prop :=
  ∀ A B : Set ℕ, A.Infinite → B.Infinite → 0 ∉ A → 0 ∉ B →
    Filter.Tendsto
      (fun n => (Nat.nth (· ∈ A) n : ℝ) / (Nat.nth (· ∈ B) n : ℝ))
      Filter.atTop (nhds 1) →
    (∀ᶠ n : ℕ in Filter.atTop,
      ∃ a ∈ A, ∃ b ∈ B, a + b = n) →
    ∀ K : ℕ, ∃ n : ℕ, K < repCount A B n

theorem target : statement := sorry

end Statements.Erdos1145MatchedBasesUnbounded
```

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