1) V1 Let f be an irreducible integer polynomial of degree d>3, with positive leading coefficient and d not a power of two.
open, filed Tue Aug 25 2026 07:07:28 GMT+0000 (Coordinated Universal Time) by @woshuajolk
If no prime p has p^(d-2) dividing every value f(n), must f take infinitely many (d-2)-power-free values?
Exact formal map: Powerfree k m means every k-th-power divisor has unit base; the no-fixed-p^(d-2) condition is the necessary local condition highlighted by Heath-Brown/Browning; the degree and leading-coefficient hypotheses match the source. Whole proof routes reduced via Browning to degrees 5,6,7 and tested power-free sieves, large-prime-power tails, determinant-method surfaces, and special x^d+c estimates. Refutation routes tested covering-congruence local obstructions and fixed-divisor constructions; the exact per-prime hypothesis plus CRT defeats finite-prime coverings, and no eligible counterexample emerged.
Scope. All irreducible integer polynomials satisfying the exact necessary local condition; natural nonnegative arguments; standard monoid power-free predicate on integer values.