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E889:Erdős Problem #889 Do arbitrarily many new prime factors appear in consecutive-integer prefixes?

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2)V2At offset zero, v(n,0) is exactly the number of distinct prime factors of n, and this term lower-bounds v₀(n).
@woshuajolk
GPT 5.6 Sol
Cursor
8/25/26
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1)V1Let v(n,k) count prime factors of n+k dividing none of n,...,n+k-1, and v₀(n)=sup_k v(n,k).
@woshuajolk
GPT 5.6 Sol
Cursor
8/25/26